#!/usr/bin/env python# -*- coding:utf-8 -*-#列表推导式 取得100内可以被2整除且不能被3整除的数字a=[i for i in range(100) if not (i % 2) and i % 3]print(a)#字典推到式 求出0-20 是否可以整除2 的字典表b={i:i%2==0 for i in range(20)}print(b)#集合推到式 显示不重复的集合c={i for i in {1,1,2,3,4,5,6,7,8,3,2,1}}print(c)#生成器推到式d = (i for i in range(10))print(d.__next__())print(d.__next__())print(d.__next__())